2023 AMC 8 Problems/Problem 22: Difference between revisions
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~MrThinker | ~MrThinker | ||
Solution 2: | |||
We assign the value a as a term in this sequence. | |||
<cmath>a_1->C</cmath> | |||
<cmath>a_2->D</cmath> | |||
<cmath>a_3->C \cdot D</cmath> | |||
<cmath>a_4->C\cdot D^2</cmath> | |||
<cmath>a_5->C^2 \cdot D^3</cmath> | |||
<cmath>a_6->C^3 \cdot D^5 -> 4000</cmath> | |||
When we prime factorize <cmath>4000, we see that </cmath>4000 = 2^5 \cdot 5^3<math></math> | |||
We get C=5 and D=2 | |||
Remember C is the first number so, | |||
Our answer is <math>\boxed{\text{(D)}5}</math> | |||
==Animated Video Solution== | ==Animated Video Solution== | ||
Revision as of 18:43, 24 January 2023
Problem
In a sequence of positive integers, each term after the second is the product of the previous two terms. The sixth term is
. What is the first term?
Solution
Suppose the first two terms were
and
. Then, the next terms would be
,
,
, and
. Since
is the sixth term, this must be equal to
. So,
. Trying out the choices, we get that
,
, which means that the answer is
~MrThinker
Solution 2:
We assign the value a as a term in this sequence.
When we prime factorize
4000 = 2^5 \cdot 5^3$$ (Error compiling LaTeX. Unknown error_msg)
We get C=5 and D=2 Remember C is the first number so, Our answer is![]()
Animated Video Solution
~Star League (https://starleague.us)