Art of Problem Solving

2004 AIME I Problems/Problem 10: Difference between revisions

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== Problem ==
== Problem ==
A circle of radius 1 is randomly placed in a 15-by-36 rectangle <math> ABCD </math> so that the circle lies completely within the rectangle. Given that the probability that the circle will not touch diagonal <math> AC </math> is <math> m/n, </math> where <math> m </math> and <math> n </math> are relatively prime positive integers. Find <math> m + n. </math>
A [[circle]] of [[radius]] 1 is randomly placed in a 15-by-36 [[rectangle]] <math> ABCD </math> so that the circle lies completely within the rectangle. Given that the p[[robability]] that the circle will not touch diagonal <math> AC </math> is <math> m/n, </math> where <math> m </math> and <math> n </math> are relatively prime positive integers. Find <math> m + n. </math>


== Solution ==
== Solution ==
{{solution}}
[[Image:2004_I_AIME-10.png]]


== See also ==
== See also ==
* [[2004 AIME I Problems/Problem 9| Previous problem]]
{{AIME box|year=2004|num-b=9|num-a=11}}


* [[2004 AIME I Problems/Problem 11| Next problem]]
[[Category:Intermediate Geometry Problems]]
 
* [[2004 AIME I Problems]]

Revision as of 18:30, 13 October 2007

Problem

A circle of radius 1 is randomly placed in a 15-by-36 rectangle $ABCD$ so that the circle lies completely within the rectangle. Given that the probability that the circle will not touch diagonal $AC$ is $m/n,$ where $m$ and $n$ are relatively prime positive integers. Find $m + n.$

Solution

See also

2004 AIME (ProblemsAnswer KeyResources)
Preceded by
Problem 9
Followed by
Problem 11
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All AIME Problems and Solutions