1997 PMWC Problems/Problem I1: Difference between revisions

Revision as of 16:14, 8 October 2007

Problem

Evaluate $29 \frac{27}{28} \times 27\frac{14}{15}$ .

Solution

$\frac{29 \cdot 28 + 14}{28} \cdot \frac{27 \cdot 15 + 24}{15} = \frac{839 \cdot 419}{420} = \frac{839(420 - 1)}{420} = 839 - \frac{839}{420} = 837 \frac{1}{420}$

@@ Line 1: / Line 1: @@
-1/420
+== Problem ==
+Evaluate <math>29 \frac{27}{28} \times 27\frac{14}{15}</math>.
+== Solution ==
+<math>\frac{29 \cdot 28 + 14}{28} \cdot \frac{27 \cdot 15 + 24}{15} = \frac{839 \cdot 419}{420} = \frac{839(420 - 1)}{420} = 839 - \frac{839}{420} = 837 \frac{1}{420}</math>
+== See also ==
+{{PMWC box|year=1997|before=First question|num-a=I2}}
+[[Category:Introductory Algebra Problems]]

1997 PMWC (Problems)
Preceded by First question	Followed by Problem I2
I: 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 T: 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10

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1997 PMWC Problems/Problem I1: Difference between revisions

Revision as of 16:14, 8 October 2007

Problem

Solution

See also