2021 Fall AMC 12B Problems/Problem 10: Difference between revisions
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Together, the sum of all such possible values of <math>t</math> is <math>20+80+50+230=\boxed{\textbf{(E)} \: 380}.</math> | Together, the sum of all such possible values of <math>t</math> is <math>20+80+50+230=\boxed{\textbf{(E)} \: 380}.</math> | ||
<u><b>Remark</b></u> | |||
The following diagram shows Cases 1, 2, and 3 in red, blue, and green, respectively: | |||
~Steven Chen (www.professorchenedu.com) ~Wilhelm Z ~MRENTHUSIASM | ~Steven Chen (www.professorchenedu.com) ~Wilhelm Z ~MRENTHUSIASM | ||
Revision as of 02:22, 28 January 2022
Problem
What is the sum of all possible values of
between
and
such that the triangle in the coordinate plane whose vertices are
is isosceles?
Solution
Let
and
We apply casework to the legs of isosceles

Note that
must be the midpoint of
It follows that
so 

Note that
must be the midpoint of
It follows that
so 

Note that
must be the midpoint of
It follows that
or
so
or
Together, the sum of all such possible values of
is
Remark
The following diagram shows Cases 1, 2, and 3 in red, blue, and green, respectively:
~Steven Chen (www.professorchenedu.com) ~Wilhelm Z ~MRENTHUSIASM
| 2021 Fall AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 9 |
Followed by Problem 11 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
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