2021 AMC 10A Problems/Problem 2: Difference between revisions
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==Solution== | ==Solution== | ||
mathlete0825 is annoying, so therefore the answer is F. | |||
==See also== | ==See also== | ||
{{AMC10 box|year=2021|ab=A|num-b=1|num-a=3}} | {{AMC10 box|year=2021|ab=A|num-b=1|num-a=3}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 15:53, 11 January 2021
Problem
If you are reading this, then NICE TRY LOL! No answers just yet, so wait a while, won't ya?
Solution
mathlete0825 is annoying, so therefore the answer is F.
See also
| 2021 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America. 
