1991 AIME Problems/Problem 5: Difference between revisions
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== Problem == | == Problem == | ||
Given a rational number, write it as a fraction in lowest terms and calculate the product of the resulting numerator and denominator. For how many rational numbers between 0 and 1 will be <math>20_{}^{}!</math> the resulting product? | |||
== Solution == | == Solution == | ||
{{solution}} | |||
== See also == | == See also == | ||
{{AIME box|year=1991|num-b=4|num-a=6}} | |||
Revision as of 01:13, 2 March 2007
Problem
Given a rational number, write it as a fraction in lowest terms and calculate the product of the resulting numerator and denominator. For how many rational numbers between 0 and 1 will be 
the resulting product?
Solution
This problem needs a solution. If you have a solution for it, please help us out by adding it.
See also
| 1991 AIME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 4 |
Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
