1955 AHSME Problems/Problem 22: Difference between revisions
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The positive difference between the offers is therefore <math>5760 - 5415 = \fbox{\textbf{(D)} \textdollar{345}}</math> | The positive difference between the offers is therefore <math>5760 - 5415 = \fbox{\textbf{(D)} \textdollar{345}}</math> | ||
== See Also == | |||
{{AHSME box|year=1955|num-b=21|num-a=23}} | |||
{{MAA Notice}} | |||
Latest revision as of 22:14, 9 August 2020
Problem 22
On a 
order a merchant has a choice between three successive discounts of 
%, %, and 
% and
three successive discounts of 
%, 
%, and %. By choosing the better offer, he can save:
Solution
In order to solve this problem, we can simply try both paths and finding the positive difference between the two.
The first path goes 
The second path goes 
The positive difference between the offers is therefore 
See Also
| 1955 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 21 |
Followed by Problem 23 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America. 
