1995 AIME Problems/Problem 13: Difference between revisions
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== Problem == | == Problem == | ||
Let <math>\displaystyle f(n)</math> be the integer closest to <math>\displaystyle \sqrt[4]{n}.</math> Find <math>\displaystyle \sum_{k=1}^{1995}\frac 1{f(k)}.</math> | |||
== Solution == | == Solution == | ||
== See also == | == See also == | ||
* [[1995_AIME_Problems/Problem_12|Previous Problem]] | |||
* [[1995_AIME_Problems/Problem_14|Next Problem]] | |||
* [[1995 AIME Problems]] | * [[1995 AIME Problems]] | ||
Revision as of 00:29, 22 January 2007
Problem
Let 
be the integer closest to ![$\displaystyle \sqrt[4]{n}.$](http://latex.artofproblemsolving.com/9/3/4/934e17c1e55282d831e11908844f89b0a2e8c9da.png)
Find 
