2020 AMC 10A Problems/Problem 1: Difference between revisions

Revision as of 14:07, 27 May 2020

Problem

What value of $x$ satisfies $x- \frac{3}{4} = \frac{5}{12} - \frac{1}{3}?$

$\textbf{(A)}\ -\frac{2}{3}\qquad\textbf{(B)}\ \frac{7}{36}\qquad\textbf{(C)}\ \frac{7}{12}\qquad\textbf{(D)}\ \frac{2}{3}\qquad\textbf{(E)}\ \frac{5}{6}$

Solution

Adding $\frac{3}{4}$ to both sides, $x= \frac{5}{12} - \frac{1}{3} + \frac{3}{4} = \frac{5}{12} - \frac{4}{12} + \frac{9}{12}=\boxed{\textbf{(E) }\frac{5}{6}}$ .

Video Solution

https://youtu.be/WUcbVNy2uv0

~IceMatrix

https://www.youtube.com/watch?v=7-3sl1pSojc

~bobthefam

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2020 AMC 10A Problems/Problem 1: Difference between revisions

Revision as of 14:07, 27 May 2020

Contents

Problem

Solution

Video Solution

See Also

@@ Line 12: / Line 12: @@
 ~IceMatrix
+https://www.youtube.com/watch?v=7-3sl1pSojc
+~bobthefam
 == See Also ==