2020 AMC 10B Problems/Problem 1: Difference between revisions
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==Problem | ==Problem== | ||
<math>\textbf{(A)}\ \qquad\textbf{(B)}\ \qquad\textbf{(C)}\ \qquad\textbf{(D)}\ \qquad\textbf{(E)}\ </math> | What is the value of | ||
<cmath>1-(-2)-3-(-4)-5-(-6)?</cmath> | |||
<math>\textbf{(A)}\ -20 \qquad\textbf{(B)}\ -3 \qquad\textbf{(C)}\ 3 \qquad\textbf{(D)}\ 5 \qquad\textbf{(E)}\ 21</math> | |||
==Solution== | |||
We know that when we subtract negative numbers, <math>a-(-b)=a+b</math>. | |||
The equation becomes <math>1+2-3+4-5+6 = \boxed{\textbf{(D)}\ 5}</math> | |||
== Solution == | == Solution == | ||
Revision as of 15:25, 7 February 2020
Problem
What is the value of
![\[1-(-2)-3-(-4)-5-(-6)?\]](http://latex.artofproblemsolving.com/9/4/c/94cdfebdc087637cc5450da458e0db822c81da88.png)
Solution
We know that when we subtract negative numbers, 
.
The equation becomes 
Solution
Solution
Video Solution
YouTube Link
See Also
| 2020 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
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