2009 AMC 10A Problems/Problem 1: Difference between revisions
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== Problem == | == Problem == | ||
One | One can, can hold <math>12</math> ounces of soda, what is the minimum number of cans needed to provide a gallon (<math>128</math> ounces) of soda? | ||
<math>\textbf{(A)}\ 7\qquad | <math>\textbf{(A)}\ 7\qquad | ||
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\textbf{(C)}\ 9\qquad | \textbf{(C)}\ 9\qquad | ||
\textbf{(D)}\ 10\qquad | \textbf{(D)}\ 10\qquad | ||
\textbf{(E)}\ 11</math> | \textbf{(E)}\ 11</math> | ||
== Solution 1 == | == Solution 1 == | ||
Revision as of 19:40, 29 January 2020
Problem
One can, can hold 
ounces of soda, what is the minimum number of cans needed to provide a gallon (
ounces) of soda?
Solution 1
cans would hold 
ounces, but 
, so 
cans are required. Thus, the answer is 
.
Solution 2
We want to find 
because there are a whole number of cans.
| 2009 AMC 10A (Problems • Answer Key • Resources) | ||
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Followed by Problem 2 | |
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| All AMC 10 Problems and Solutions | ||
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