1990 AJHSME Problems/Problem 19: Difference between revisions
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<math>p</math> is a person seated, <math>o</math> is an empty seat | <math>p</math> is a person seated, <math>o</math> is an empty seat | ||
The pattern of seating that results in the fewest occupied seats is | The pattern of seating that results in the fewest occupied seats is opoopoopoo...po | ||
we can group the seats in 3s | we can group the seats in 3s | ||
opo opo opo ... opo | |||
there are a total of < | there are a total of <math>\boxed{B}</math> groups | ||
==See Also== | ==See Also== | ||
Revision as of 07:22, 15 November 2019
Problem
There are
seats in a row. What is the fewest number of seats that must be occupied so the next person to be seated must sit next to someone?
Solution
is a person seated,
is an empty seat
The pattern of seating that results in the fewest occupied seats is opoopoopoo...po we can group the seats in 3s opo opo opo ... opo
there are a total of
groups
See Also
| 1990 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 18 |
Followed by Problem 20 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||