2019 Mock AMC 10B Problems/Problem 2: Difference between revisions
No edit summary |
No edit summary |
||
| Line 1: | Line 1: | ||
Simply choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have <math>{6 \choose 3}=15</math> | Simply choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have <math>{6 \choose 3}=15</math> | ||
<cmath>\boxed{\bold{C}}</cmath> | |||
<cmath>\bold{25}</cmath> | |||
Revision as of 23:30, 22 September 2019
Simply choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have 
![\[\boxed{\bold{C}}\]](http://latex.artofproblemsolving.com/7/d/1/7d12f186788eb60eec972d55f8e7d881de7517c1.png)
![\[\bold{25}\]](http://latex.artofproblemsolving.com/d/9/0/d90c79a80cadee74cc0df671a2347aafcfc7e234.png)
