Art of Problem Solving

2019 Mock AMC 10B Problems/Problem 2: Difference between revisions

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Created page with "Simplify choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have <math>{6 \choose 3}=15</math>"
 
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Simplify choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have <math>{6 \choose 3}=15</math>
Simply choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have <math>{6 \choose 3}=15</math>

Revision as of 23:29, 22 September 2019

Simply choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have ${6 \choose 3}=15$