1993 AHSME Problems/Problem 1: Difference between revisions

Latest revision as of 23:27, 29 November 2016

For integers $a,b,$ and $c$ define $\fbox{a,b,c}$ to mean $a^b-b^c+c^a$ . Then $\fbox{1,-1,2}$ equals:

$\text{(A) } -4\quad \text{(B) } -2\quad \text{(C) } 0\quad \text{(D) } 2\quad \text{(E) } 4$

Plug in the values for $a,b,c$ and you get $1^{-1} - (-1)^2 + 2^1 \Rightarrow 1-1+2 \Rightarrow \fbox{2}$

$\fbox{D}$

1993 AHSME (Problems • Answer Key • Resources)
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All AHSME Problems and Solutions

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 == Solution ==
-Plug in the values for <math>a,b,c</math> and you get <math>1^-1 - (-1)^2 + 2^1 \Rightarrow 1-1+2 \Rightarrow \fbox{2}</math>
+Plug in the values for <math>a,b,c</math> and you get <math>1^{-1} - (-1)^2 + 2^1 \Rightarrow 1-1+2 \Rightarrow \fbox{2}</math>
 <math>\fbox{D}</math>