1992 AHSME Problems/Problem 5: Difference between revisions

Latest revision as of 15:21, 5 August 2016

$6^6+6^6+6^6+6^6+6^6+6^6=$

$\text{(A) } 6^6 \quad \text{(B) } 6^7\quad \text{(C) } 36^6\quad \text{(D) } 6^{36}\quad \text{(E) } 36^{36}$

We notice that $6^6+6^6+6^6+6^6+6^6+6^6=6(6^6)=\boxed{\textbf{(B) }6^7}$ .

1992 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 4	Followed by Problem 6
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30
All AHSME Problems and Solutions

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 == Solution ==
-We notice that <math>6^6+6^6+6^6+6^6+6^6+6^6=6(6^6)=\textbf{(B) }6^7</math>.
+We notice that <math>6^6+6^6+6^6+6^6+6^6+6^6=6(6^6)=\boxed{\textbf{(B) }6^7}</math>.
 == See also ==