2016 AMC 10A Problems/Problem 14: Difference between revisions
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The amount of twos in our sum ranges from <math>0</math> to <math>1008</math>, with differences of <math>3</math> because <math>2 \cdot 3 = lcm(2, 3)</math>. | The amount of twos in our sum ranges from <math>0</math> to <math>1008</math>, with differences of <math>3</math> because <math>2 \cdot 3 = lcm(2, 3)</math>. | ||
The possible amount of twos is <math>\frac{1008 - 0}{ | The possible amount of twos is <math>\frac{1008 - 0}{3} + 1 \Rightarrow \boxed{\textbf{(C)} 337}</math> | ||
Revision as of 17:59, 3 February 2016
Solution
The amount of twos in our sum ranges from 
to 
, with differences of 
because 
.
The possible amount of twos is 
