2002 AMC 10B Problems/Problem 18: Difference between revisions

Latest revision as of 15:15, 29 July 2011

Redirect to:

@@ Line 1: / Line 1: @@
-== Problem ==
+#REDIRECT[[2002 AMC 12B Problems/Problem 14]]
-Four distinct circles are drawn in a plane. What is the maximum number of points where at least two of the circles intersect?
-<math>\textbf{(A) } 8\qquad \textbf{(B) } 9\qquad \textbf{(C) } 10\qquad \textbf{(D) } 12\qquad \textbf{(E) } 16</math>
-== Solution ==
-We know that <math>2</math> distinct circles can intersect at no more than <math>2</math> points. Thus <math>4</math> circles can intersect at <math>2 \times 4= \boxed{\textbf{(D)}\ 8}</math> points total.