1985 AJHSME Problems/Problem 12: Difference between revisions
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[[Category:Introductory Geometry Problems]] | [[Category:Introductory Geometry Problems]] | ||
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Revision as of 16:05, 3 July 2013
Problem
A square and a triangle have equal perimeters. The lengths of the three sides of the triangle are 
, 
and 
. The area of the square is
Solution
We are given the three side lengths of the triangle, so we can compute the perimeter of the triangle to be 
. The square has the same perimeter as the triangle, so its side length is 
. Finally, the area of the square is 
, which is choice 
See Also
| 1985 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 11 |
Followed by Problem 13 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America. 
