User:Tonypr: Difference between revisions
No edit summary |
No edit summary |
||
| Line 4: | Line 4: | ||
Proof <math>2=1</math>: | Proof <math>2=1</math>: | ||
Suppose that <math>a=b</math> | |||
<math> | |||
\begin{eqnarray*} | |||
a&=&b\\ | |||
a^2&=&ab\\ | |||
a^2-b^2&=&ab-b^2\\ | |||
(a+b)(a-b)&=&b(a-b)\\ | |||
a+b&=&b\\ | |||
b+b&=&b\\ | |||
2b&=&b\\ | |||
2&=&1 | |||
\end{eqnarray*} | |||
</math> | |||
Revision as of 22:39, 23 May 2009
Awesome math solver from Puerto Rico, soon to be International Math Olympiad.
Proof 
:
Suppose that 
$\begin{eqnarray*} a&=&b\\ a^2&=&ab\\ a^2-b^2&=&ab-b^2\\ (a+b)(a-b)&=&b(a-b)\\ a+b&=&b\\ b+b&=&b\\ 2b&=&b\\ 2&=&1 \end{eqnarray*}$ (Error compiling LaTeX. Unknown error_msg)
