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2005 AMC 12B Problems: Difference between revisions

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== Problem 1 ==
== Problem 1 ==
Two is <math>10\%</math> of <math>x</math> and <math>20\%</math> of <math>y</math>.  What is <math>x-y</math>?
<math>
\mathrm{(A)}\ 1      \qquad
\mathrm{(B)}\ 2      \qquad
\mathrm{(C)}\ 5      \qquad
\mathrm{(D)}\ 10      \qquad
\mathrm{(E)}\ 20
</math>


[[2005 AMC 12B Problems/Problem 1|Solution]]
[[2005 AMC 12B Problems/Problem 1|Solution]]

Revision as of 20:28, 17 April 2009

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Problem 1

Two is $10\%$ of $x$ and $20\%$ of $y$. What is $x-y$?

$\mathrm{(A)}\ 1 \qquad \mathrm{(B)}\ 2 \qquad \mathrm{(C)}\ 5 \qquad \mathrm{(D)}\ 10 \qquad \mathrm{(E)}\ 20$

Solution

Problem 2

Solution

Problem 3

Solution

Problem 4

Solution

Problem 5

Solution

Problem 6

Solution

Problem 7

Solution

Problem 8

Solution

Problem 9

Solution

Problem 10

Solution

Problem 11

Solution

Problem 12

Solution

Problem 13

Solution

Problem 14

Solution

Problem 15

Solution

Problem 16

Solution

Problem 17

Solution

Problem 18

Solution

Problem 19

Solution

Problem 20

Solution

Problem 21

Solution

Problem 22

Solution

Problem 23

Solution

Problem 24

Solution

Problem 25

Solution

See also

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