2002 AMC 10A Problems/Problem 1: Difference between revisions
New page: ==Problem== The ratio <math>\frac{10^{2000}+10^{2002}}{10^{2001}+10^{2001}}</math> is closest to which of the following numbers? <math>\text{(A)}\ 0.1 \qquad \text{(B)}\ 0.2 \qquad \text{... |
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==Solution== | ==Solution== | ||
We factor <math>\frac{10^{2000}+10^{2002}}{10^{2001}+10^{2001}}</math> as <math>\frac{10^{2000}(1+100)}{10^{2001}(1+1)}=\frac{101}{20}</math>. As <math>\frac{101}{20}=5.05</math>, our answer is <math>\text{(D)}\ 5 \qquad</math>. | We factor <math>\frac{10^{2000}+10^{2002}}{10^{2001}+10^{2001}}</math> as <math>\frac{10^{2000}(1+100)}{10^{2001}(1+1)}=\frac{101}{20}</math>. As <math>\frac{101}{20}=5.05</math>, our answer is <math>\text{(D)}\ 5 \qquad</math>. | ||
==See Also== | |||
{{AMC10 box|year=2002|ab=A|before=First question|num-a=2}} | |||
[[Category:Introductory Algebra Problems]] | |||
Revision as of 16:59, 26 December 2008
Problem
The ratio 
is closest to which of the following numbers?
Solution
We factor as 
. As 
, our answer is 
.
See Also
| 2002 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by First question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
