2025 AMC 10B Problems: Difference between revisions
| Line 12: | Line 12: | ||
==Problem 2== | ==Problem 2== | ||
The residents of Mathville grow special types of fruit, afs, efs, ifs, ofs, and ufs. <imath>2</imath> afs weigh as much as <imath>3</imath> efs, <imath>5</imath> ifs weigh as much as <imath>6</imath> ofs, and <imath>7</imath> ofs weigh as much as <imath>8</imath> ufs. Considering that <imath>11</imath> afs are equivalent to the weight of <imath>13</imath> ufs, how many efs would amount to the weight of <imath>1</imath> if? | |||
==Problem 3== | ==Problem 3== | ||
Revision as of 10:54, 10 November 2025
| 2025 AMC 10B (Answer Key) Printable versions: • AoPS Resources • PDF | ||
|
Instructions
| ||
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
Problem 1
What is the value of
?
Problem 2
The residents of Mathville grow special types of fruit, afs, efs, ifs, ofs, and ufs.
afs weigh as much as
efs,
ifs weigh as much as
ofs, and
ofs weigh as much as
ufs. Considering that
afs are equivalent to the weight of
ufs, how many efs would amount to the weight of
if?
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
See Also
| 2025 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by 2025 AMC 10A Problems |
Followed by 2026 AMC 10A Problems | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America.