2025 AMC 12A Problems/Problem 7: Difference between revisions

Revision as of 16:38, 6 November 2025

Solution 1: Taking the logarithm of both sides and using n = 5, we have:

$log$ $k$ * $5^am^b$ $=$ $4+2logm$ , which we can rewrite as: $log$ $k$ * $5^am^b$ $=$ $log10^4*m^2$

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 Taking the logarithm of both sides and using n = 5, we have:
-<imath>log</imath> <imath>k</imath> * <imath>5^am^b</imath> = <imath>4+2logm</imath>
+<imath>log</imath> <imath>k</imath> * <imath>5^am^b</imath> <imath>=</imath> <imath>4+2logm</imath>, which we can rewrite as:
+<imath>log</imath> <imath>k</imath> * <imath>5^am^b</imath> <imath>=</imath> <imath>log10^4*m^2</imath>