2025 AMC 12A Problems/Problem 7: Difference between revisions

Revision as of 16:34, 6 November 2025

Solution 1: Taking the logarithm of both sides in the first equation, we have:

$log kn^am^b$

Revision as of 16:33, 6 November 2025 view source Cyrus825 (talk \| contribs) editor 35 edits No edit summary ← Older edit		Revision as of 16:34, 6 November 2025 view source Cyrus825 (talk \| contribs) editor 35 edits No edit summary Newer edit →
Line 2:		Line 2:
	Taking the logarithm of both sides in the first equation, we have:		Taking the logarithm of both sides in the first equation, we have:

	~~log v = log k~~<imath>n^~~a</imath> <imath>m~~^b</imath>		<imath>log kn^am^b</imath>