Art of Problem Solving

2006 AMC 12A Problems/Problem 1: Difference between revisions

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{{duplicate|[[2006 AMC 12A Problems|2006 AMC 12A #1]] and [[2006 AMC 10A Problems/Problem 1|2008 AMC 10A #1]]}}
== Problem ==
== Problem ==
Sandwiches at Joe's Fast Food cost <math>\</math>3 each and sodas cost <math>\</math>2 each. How many dollars will it cost to purchase <math>5</math> sandwiches and <math>8</math> sodas?
Sandwiches at Joe's Fast Food cost <math>\</math>3 each and sodas cost <math>\</math>2 each. How many dollars will it cost to purchase <math>5</math> sandwiches and <math>8</math> sodas?
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== See also ==
== See also ==
{{AMC12 box|year=2006|ab=A|before=First Question|num-a=2}}
{{AMC12 box|year=2006|ab=A|before=First Question|num-a=2}}
{{AMC10 box|year=2006|ab=A|before=First Question|num-a=2}}


[[Category:Introductory Algebra Problems]]
[[Category:Introductory Algebra Problems]]

Revision as of 23:01, 27 April 2008

The following problem is from both the 2006 AMC 12A #1 and 2008 AMC 10A #1, so both problems redirect to this page.

Problem

Sandwiches at Joe's Fast Food cost $\$3 each and sodas cost $\$2 each. How many dollars will it cost to purchase $5$ sandwiches and $8$ sodas?

$\mathrm{(A)}\ 31\qquad\mathrm{(B)}\ 32\qquad\mathrm{(C)}\ 33\qquad\mathrm{(D)}\ 34\qquad\mathrm{(E)}\ 35$

Solution

The $5$ sandwiches cost $5\cdot 3=15$ dollars. The $8$ sodas cost $8\cdot 2=16$ dollars. In total, the purchase costs $15+16=31$ dollars. The answer is $\mathrm{(A)}$.

See also

2006 AMC 12A (ProblemsAnswer KeyResources)
Preceded by
First Question
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions
2006 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
First Question
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions