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2014 CEMC Gauss (Grade 8) Problems/Problem 5: Difference between revisions

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The smallest of these numbers is <math>1001</math>. Thus, the answer is <math>\boxed {\textbf {(D) } -1001}</math>.
The smallest of these numbers is <math>1001</math>. Thus, the answer is <math>\boxed {\textbf {(D) } -1001}</math>.
~anabel.disher
{{CEMC box|year=2014|competition=Gauss (Grade 8)|num-b=4|num-a=6}}

Latest revision as of 11:29, 18 October 2025

Problem

Which of the following integers is closest to zero?

$\text{ (A) }\ -1101\qquad\text{ (B) }\ 1011\qquad\text{ (C) }\ -1010\qquad\text{ (D) }\ -1001\qquad\text{ (E) }\ 1110$

Solution

We need to find the number that has the least distance to 0. To do this, we can take the absolute value of each number, and see which number is the lowest:

$|-1101| = 1101$

$|1011| = 1011$

$|-1010| = 1010$

$|-1001| = 1001$

$|1110| = 1110$

The smallest of these numbers is $1001$. Thus, the answer is $\boxed {\textbf {(D) } -1001}$.

~anabel.disher

2014 CEMC Gauss (Grade 8) (Problems • Answer Key • Resources)
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CEMC Gauss (Grade 8)
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