Art of Problem Solving

2025 AMC 8 Problems/Problem 21: Difference between revisions

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==Problem==


The Konigsberg School has assigned grades 1 through 7 to pods <math>A</math> through <math>G</math>, one grade per
The Konigsberg School has assigned grades 1 through 7 to pods <math>A</math> through <math>G</math>, one grade per
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levels. (For example, grades 1 and 2 will not be in pods directly connected by a walkway.) What is
levels. (For example, grades 1 and 2 will not be in pods directly connected by a walkway.) What is
the sum of the grade levels assigned to pods <math>C, E</math>, and <math>F</math>?
the sum of the grade levels assigned to pods <math>C, E</math>, and <math>F</math>?


<math>\textbf{(A)}~12\qquad\textbf{(B)}~13\qquad\textbf{(C)}~14\qquad\textbf{(D)}~15\qquad\textbf{(E)}~16</math>
<math>\textbf{(A)}~12\qquad\textbf{(B)}~13\qquad\textbf{(C)}~14\qquad\textbf{(D)}~15\qquad\textbf{(E)}~16</math>


==Solution 1==
==Solution 1==
Currently no diagram, but by logic bash, we can arrive at the solution of <math>12</math>
Currently no diagram, but by logic bash, we can arrive at the solution of <math>12</math>


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==Video Solution by Thinking Feet==
==Video Solution by Thinking Feet==
https://youtu.be/PKMpTS6b988
https://youtu.be/PKMpTS6b988
==See Also==
{{AMC8 box|year=2025|num-b=20|num-a=22}}
{{MAA Notice}}

Revision as of 19:12, 30 January 2025

Problem

The Konigsberg School has assigned grades 1 through 7 to pods $A$ through $G$, one grade per pod. Some of the pods are connected by walkways, as shown in the figure below. The school noticed that each pair of connected pods has been assigned grades differing by 2 or more grade levels. (For example, grades 1 and 2 will not be in pods directly connected by a walkway.) What is the sum of the grade levels assigned to pods $C, E$, and $F$?

$\textbf{(A)}~12\qquad\textbf{(B)}~13\qquad\textbf{(C)}~14\qquad\textbf{(D)}~15\qquad\textbf{(E)}~16$

Solution 1

Currently no diagram, but by logic bash, we can arrive at the solution of $12$

~shreyan.chethan

Video Solution by Thinking Feet

https://youtu.be/PKMpTS6b988

See Also

2025 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 20
Followed by
Problem 22
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

These problems are copyrighted © by the Mathematical Association of America.