2024 AMC 8 Problems/Problem 1: Difference between revisions

Revision as of 21:08, 7 January 2025

Problem

What is the ones digit of: $222{,}222-22{,}222-2{,}222-222-22-2?$ $\textbf{(A) } 0\qquad\textbf{(B) } 2\qquad\textbf{(C) } 4\qquad\textbf{(D) } 6\qquad\textbf{(E) } 8$

Solution 1

We can rewrite the expression as $222,222-(22,222+2,222+222+22+2)$ . We note that the units digit of $22,222+2,222+222+22+2$ is $0$ because all the units digits of the five numbers are $2$ and $5\cdot2=10$ , which has a units digit of $0$ . Now, we have something with a units digit of $0$ subtracted from $222,222$ , and so the units digit of this expression is $\boxed{\textbf{(B) } 2}$ .

Solution 2

$222,222-22,222 = 200,000$ $200,000 - 2,222 = 197778$ $197778 - 222 = 197556$ $197556 - 22 = 197534$ $197534 - 2 = 1957532$ So our answer is $\boxed{\textbf{(B) } 2}$ .

Solution 3

We only care about the units digits. Thus, $2-2$ ends in $0$ , $0-2$ after regrouping(10-2) ends in $8$ , $8-2$ ends in $6$ , $6-2$ ends in $4$ , and $4-2$ ends in $\boxed{\textbf{(B) } 2}$ .

Solution 4

We just take the units digit of each and subtract, adding an extra ten to the first number so we don't get a negative number: $(12-2)-(2+2+2+2)=10-8=\boxed{\textbf{(B) } 2}$

Solution 5

$222{,}222-22{,}222-2{,}222-222-22-2\equiv2-2-2-2-2\equiv-8\equiv\boxed{\textbf{(B) } 2}\pmod10$

Video Solution by Central Valley Math Circle (Goes through full thought process)

https://youtu.be/-XcShDyuZIo

~mr_mathman

Video Solution 1 (Detailed Explanation)

https://youtu.be/jqsbMWhTYRg

~ ChillGuyDoesMath :)

Video Solution 2 (MATH-X)

https://youtu.be/BaE00H2SHQM?si=O0O0g7qq9AbhQN9I&t=130

Video Solution 3 (A Clever Explanation You’ll Get Instantly)

https://youtu.be/5ZIFnqymdDQ?si=IbHepN2ytt7N23pl&t=53

~hsnacademy

Video Solution 4 (Quick and Easy!)

https://youtu.be/Ol1seWX0xHY

~Education, the Study of Everything

Video Solution by Interstigation

https://youtu.be/ktzijuZtDas&t=36

Video Solution by Daily Dose of Math

https://youtu.be/bSPWqeNO11M?si=HIzlxPjMfvGM5lxR

~Thesmartgreekmathdude

Video Solution by Dr. David

https://youtu.be/RzPadkHd3Yc

Video Solution by WhyMath

https://youtu.be/i4mcj3jRTxM

@@ Line 1: / Line 1: @@
-==Problem 1==
+==Problem==
 What is the ones digit of: <cmath>222{,}222-22{,}222-2{,}222-222-22-2?</cmath>
 <math>\textbf{(A) } 0\qquad\textbf{(B) } 2\qquad\textbf{(C) } 4\qquad\textbf{(D) } 6\qquad\textbf{(E) } 8</math>
 ==Solution 1==
-We can rewrite the expression as <cmath>222,222-(22,222+2,222+222+22+2).</cmath>
+We can rewrite the expression as <math>222,222-(22,222+2,222+222+22+2)</math>. We note that the units digit of <math>22,222+2,222+222+22+2</math> is <math>0</math> because all the units digits of the five numbers are <math>2</math> and <math>5\cdot2=10</math>, which has a units digit of <math>0</math>. Now, we have something with a units digit of <math>0</math> subtracted from <math>222,222</math>, and so the units digit of this expression is <math>\boxed{\textbf{(B) } 2}</math>.
-We note that the units digit of the addition is <math>0</math> because all the units digits of the five numbers are <math>2</math> and <math>5*2=10</math>, which has a units digit of <math>0</math>.
-Now, we have something with a units digit of <math>0</math> subtracted from <math>222,222</math>. The units digit of this expression is obviously <math>2</math>, and we get <math>\boxed{B}</math> as our answer.
 ==Solution 2==
+<cmath>222,222-22,222 = 200,000</cmath>
-<math>222,222-22,222 = 200,000</math>
+<cmath>200,000 - 2,222 = 197778</cmath>
-<math>200,000 - 2,222 = 197778</math>
+<cmath>197778 - 222 = 197556</cmath>
-<math>197778 - 222 = 197556</math>
+<cmath>197556 - 22 = 197534</cmath>
-<math>197556 - 22 = 197534</math>
+<cmath>197534 - 2 = 1957532</cmath>
-<math>197534 - 2 = 1957532
-</math>
 So our answer is <math>\boxed{\textbf{(B) } 2}</math>.
 ==Solution 3==
+We only care about the units digits. Thus, <math>2-2</math> ends in <math>0</math>, <math>0-2</math> after regrouping(10-2) ends in <math>8</math>, <math>8-2</math> ends in <math>6</math>, <math>6-2</math> ends in <math>4</math>, and <math>4-2</math> ends in <math>\boxed{\textbf{(B) } 2}</math>.
-We only care about the unit's digits.
-Thus, <math>2-2</math> ends in <math>0</math>, <math>0-2</math> after regrouping(10-2) ends in <math>8</math>, <math>8-2</math> ends in <math>6</math>, <math>6-2</math> ends in <math>4</math>, and <math>4-2</math> ends in  <math>\boxed{\textbf{(B) } 2}</math>.
--unknown
-minor edits by Fireball9746
 ==Solution 4==
+We just take the units digit of each and subtract, adding an extra ten to the first number so we don't get a negative number:
+<cmath>(12-2)-(2+2+2+2)=10-8=\boxed{\textbf{(B) } 2}</cmath>
-We just take the units digit of each and subtract, or you can do it this way by adding an extra ten to the first number (so we don't get a negative number):
+== Solution 5 ==
-<cmath>(12-2)-(2+2+2+2)=10-8=2</cmath>
+<cmath>222{,}222-22{,}222-2{,}222-222-22-2\equiv2-2-2-2-2\equiv-8\equiv\boxed{\textbf{(B) } 2}\pmod10</cmath>
-Thus, we get the answer <math>\boxed{(B)}</math>
 ==Video Solution by Central Valley Math Circle (Goes through full thought process)==
@@ Line 41: / Line 29: @@
 ~mr_mathman
-== Video Solution 1 (Detailed Explanation) 🚀⚡📊 ==
+== Video Solution 1 (Detailed Explanation) ==
-Youtube Link ⬇️
 https://youtu.be/jqsbMWhTYRg
 ~ ChillGuyDoesMath :)
-==Video Solution (MATH-X)==
+==Video Solution 2 (MATH-X)==
 https://youtu.be/BaE00H2SHQM?si=O0O0g7qq9AbhQN9I&t=130
- ~Math-X
+==Video Solution 3 (A Clever Explanation You’ll Get Instantly)==
-==Video Solution (A Clever Explanation You’ll Get Instantly)==
 https://youtu.be/5ZIFnqymdDQ?si=IbHepN2ytt7N23pl&t=53
 ~hsnacademy
-==Video Solution  (Quick and Easy!)==
+==Video Solution  4 (Quick and Easy!)==
 https://youtu.be/Ol1seWX0xHY
@@ Line 68: / Line 51: @@
 ==Video Solution by Daily Dose of Math==
 https://youtu.be/bSPWqeNO11M?si=HIzlxPjMfvGM5lxR
@@ Line 74: / Line 56: @@
 ==Video Solution by Dr. David==
 https://youtu.be/RzPadkHd3Yc

2024 AMC 8 (Problems • Answer Key • Resources)
Preceded by First Problem	Followed by Problem 2
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

Page

Toolbox

Search