1955 AHSME Problems/Problem 33: Difference between revisions
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He arrives at his destination between <math>2</math> p.m. and <math>3</math> p.m. when the hands of the clock are exactly <math>180^\circ</math> apart. The trip takes: | He arrives at his destination between <math>2</math> p.m. and <math>3</math> p.m. when the hands of the clock are exactly <math>180^\circ</math> apart. The trip takes: | ||
<math> \textbf{(A)}\ \text{6 hr.}\qquad\textbf{(B)}\ \text{6 hr. 43 | <math> \textbf{(A)}\ \text{6 hr.}\qquad\textbf{(B)}\ \text{6 hr. } 43\frac{7}{11} \text{min.}\qquad\textbf{(C)}\ \text{5 hr. } 16\frac{4}{11} \text{min.}\qquad\textbf{(D)}\ \text{6 hr. 30 min.}\qquad\textbf{(E)}\ \text{none of these} </math> | ||
==Solution== | ==Solution== | ||
Latest revision as of 19:10, 15 July 2025
Problem 33
Henry starts a trip when the hands of the clock are together between 
a.m. and 
a.m.
He arrives at his destination between 
p.m. and 
p.m. when the hands of the clock are exactly 
apart. The trip takes:
Solution
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