Art of Problem Solving

2021 JMPSC Accuracy Problems/Problem 12: Difference between revisions

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==Problem==
==Problem==
A rectangle with base <math>1</math> and height <math>2</math> is inscribed in an equilateral triangle. Another rectangle with height <math>1</math> is also inscribed in the triangle. The base of the second rectangle can be written as a fully simplified fraction <math>\frac{a+b\sqrt{3}}{c}</math> such that <math>gcd(a,b,c)=1.</math> Find <math>a+b+c</math>.
A rectangle with base <math>1</math> and height <math>2</math> is inscribed in an equilateral triangle. Another rectangle with height <math>1</math> is also inscribed in the triangle. The base of the second rectangle can be written as a fully simplified fraction <math>\frac{a+b\sqrt{3}}{c}</math> such that <math>gcd(a,b,c)=1.</math> Find <math>a+b+c</math>.
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[[File:Sprint13.jpg|400px]]
[[File:Sprint13.jpg|400px]]

Revision as of 20:47, 10 July 2021

Problem

A rectangle with base $1$ and height $2$ is inscribed in an equilateral triangle. Another rectangle with height $1$ is also inscribed in the triangle. The base of the second rectangle can be written as a fully simplified fraction $\frac{a+b\sqrt{3}}{c}$ such that $gcd(a,b,c)=1.$ Find $a+b+c$.

Solution

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