2020 AMC 8 Problems/Problem 20: Difference between revisions
Icematrix2 (talk | contribs) No edit summary |
Icematrix2 (talk | contribs) No edit summary |
||
| Line 7: | Line 7: | ||
==See also== | ==See also== | ||
{{AMC8 box|year=2020| | {{AMC8 box|year=2020|num-b=19|num-a=21}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 00:19, 18 November 2020
A scientist walking through a forest recorded as integers the heights of 
trees standing in a row. She observed that each tree was either twice as tall or half as tall as the one to its right. Unfortunately some of her data was lost when rain fell on her notebook. Her notes are shown below, with blanks indicating the missing numbers. Based on her observations, the scientist was able to reconstruct the lost data. What was the average height of the trees, in meters?
![\[\begin{tabular}{|c|c|} \hline Tree 1 & \rule{0.2cm}{0.15mm} meters \\ Tree 2 & 11 meters \\ Tree 3 & \rule{0.2cm}{0.15mm} meters \\ Tree 4 & \rule{0.2cm}{0.15mm} meters \\ Tree 5 & \rule{0.2cm}{0.15mm} meters \\ \hline Average height & \rule{0.2cm}{0.15mm}.2 meters \\ \hline \end{tabular}\]](http://latex.artofproblemsolving.com/2/b/4/2b4aafba4ccdbff56d5c5253d9219b4261fe5c92.png)
Solution 1
It is not too hard to construct 
as the heights of the trees from left to right. The average is 
.
See also
| 2020 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 19 |
Followed by Problem 21 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America. 
