2020 AIME II Problems/Problem 3: Difference between revisions
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==Problem== | |||
The value of <math>x</math> that satisfies <math>\log_{2^x} 3^{20} = \log_{2^{x+3}} 3^{2020}</math> can be written as <math>\frac{m}{n}</math>, where <math>m</math> and <math>n</math> are relatively prime positive integers. Find <math>m+n</math>. | |||
==Solution== | |||
==See Also== | |||
Revision as of 15:54, 7 June 2020
Problem
The value of 
that satisfies 
can be written as 
, where 
and 
are relatively prime positive integers. Find 
.
