2002 AIME I Problems/Problem 6: Difference between revisions
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== Problem == | == Problem == | ||
The solutions to the system of equations | |||
<cmath>\log_{225}x+\log_{64}y=4</cmath> | |||
<cmath>\log_{x}225-\log_{y}64=1</cmath> | |||
are <math>(x_1,y_1)</math> and <math>(x_2,y_2)</math>. Find <math>\log_{30}\left(x_1y_1x_2y_2\right)</math> | |||
== Solution == | == Solution == | ||
Revision as of 15:31, 25 September 2007
Problem
The solutions to the system of equations
![\[\log_{225}x+\log_{64}y=4\]](http://latex.artofproblemsolving.com/f/3/b/f3b809acc2159f7bdde5e136b422fa05290d3583.png)
![\[\log_{x}225-\log_{y}64=1\]](http://latex.artofproblemsolving.com/5/e/a/5eae832801bfd19482bc439b09f9856ec8ecea9b.png)
are 
and 
. Find 
Solution
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