2019 Mock AMC 10B Problems/Problem 2: Difference between revisions

Revision as of 23:30, 22 September 2019

Simply choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have ${6 \choose 3}=15$ $\[\]$ $\boxed{\bold{C}}$ $\bold{25}$

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 Simply choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have <math>{6 \choose 3}=15</math>
-<cmath>\boxed{\bold{C}}</cmath>
+<cmath></cmath><math>\boxed{\bold{C}}</math>
-<cmath>\bold{25}</cmath>
+<math>\bold{25}</math>