Art of Problem Solving

1990 AJHSME Problems/Problem 10: Difference between revisions

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==Solution==
Looking at the positions of the letters, we see that if the date behind <math>\text{Q}</math> is <math>q</math>, then the date behind <math>\textbf{A}</math> is <math>q-6</math> and the date behind <math>\textbf{B}</math> is <math>q+6</math>. Thus, their sum is <math>2q</math>.
The date behind <math>\text{C}</math> is <math>q-7</math>, so the desired letter is the one for which the date behind it is <math>2q-(q-7)=q+7</math>. This is letter <math>\text{P}\rightarrow \boxed{\text{A}}</math>.
==See Also==
==See Also==



Revision as of 15:41, 31 July 2019

See Also

1990 AJHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 9
Followed by
Problem 11
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All AJHSME/AMC 8 Problems and Solutions

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