Art of Problem Solving

2019 AMC 12A Problems/Problem 2: Difference between revisions

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<math>a=1.5b</math>
<math>a=1.5b</math>


Therfore,
Therefore,


<math>b=a/1.5</math>
<math>b=a/1.5</math>

Revision as of 17:10, 9 February 2019

Problem

Suppose $a$ is $150\%$ of $b$. What percent of $a$ is $3b$?

$\textbf{(A) } 50 \qquad \textbf{(B) } 66\frac{2}{3} \qquad \textbf{(C) } 150 \qquad \textbf{(D) } 200 \qquad \textbf{(E) } 450$

Solution

$a=1.5b$

Therefore,

$b=a/1.5$

$3b=2a$

$2a$ is $\boxed{200}$ of $a$.

See Also

2019 AMC 12A (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions

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