1970 AHSME Problems/Problem 14: Difference between revisions
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<math>\text{(A) } \sqrt{4q+1}\quad | <math>\text{(A) } \sqrt{4q+1}\quad | ||
\text{(B) } | \text{(B) } q-1\quad | ||
\text{(C) } -\sqrt{4q+1}\quad | \text{(C) } -\sqrt{4q+1}\quad | ||
\text{(D) } q+1\quad | \text{(D) } q+1\quad | ||
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== Solution == | == Solution == | ||
<math>\ | From the quadratic equation, the two roots of the equation are <math>\frac{-p\pm\sqrt{p^2-4q}}{2}</math>. The positive difference between these roots is <math>\sqrt{p^2 - 4q}</math>. Setting <math>\sqrt{p^2-4q}=1</math> and isolating <math>p</math> gives <math>\sqrt{4q+1}</math>, or choice <math>\boxed{\text{(A)}}</math>. | ||
== See also == | == See also == | ||
Latest revision as of 00:30, 24 February 2023
Problem
Consider 
, where 
and 
are positive numbers. If the roots of this equation differ by 1, then equals
Solution
From the quadratic equation, the two roots of the equation are 
. The positive difference between these roots is 
. Setting 
and isolating gives 
, or choice 
.
See also
| 1970 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 13 |
Followed by Problem 15 | |
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