2000 AMC 10 Problems/Problem 15: Difference between revisions
New page: <math>ab=a-b</math> <math>\frac{a}{b}+\frac{b}{a}-ab=\frac{a^2+b^2}{ab}-ab=\frac{-a^2b^2+a^2+b^2}{ab}</math> <math>\frac{-a^2+2ab-b^2+a^2+b^2}{ab}=2</math>. E. |
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#REDIRECT [[2000 AMC 12 Problems/Problem 11]] | |||
Latest revision as of 22:54, 26 November 2011
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