2025 AMC 10A Problems/Problem 21: Difference between revisions

Latest revision as of 02:08, 8 November 2025

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-(Problem goes here)
+#redirect [[2025 AMC 12A Problems/Problem 15]]
-==Solution 1==
-Let our subset be <imath>\{11,12,13,...,20\}.</imath> If we add any one element from the set <imath>\{1,2,3,...,10\},</imath> we will have to remove at least one element from our current subset. Hence, the size of our set cannot exceed <imath>\boxed{\text{(C) }10}.</imath>
-~Tacos_are_yummy_1
-==See also==
-{{AMC10 box|year=2025|ab=A|num-b=20|num-a=22}}
-{{AMC12 box|year=2025|ab=A|num-b=17|num-a=19}}
-{{MAA Notice}}