Art of Problem Solving

1951 AHSME Problems/Problem 28: Difference between revisions

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==Problem==
==Problem==
The pressure <math>(P)</math> of wind on a sail varies jointly as the area <math>(A)</math> of the sail and the square of the velocity <math>(V)</math> of the wind. The pressure on a square foot is <math>1</math> pound when the velocity is <math>16</math> miles per hour. The velocity of the wind when the pressure on a square yard is <math>36</math> pounds is:
<math> \textbf{(A)}\ 10\frac{2}{3}\text{ mph}\qquad\textbf{(B)}\ 96\text{ mph}\qquad\textbf{(C)}\ 32\text{ mph}\qquad\textbf{(D)}\ 1\frac{2}{3}\text{ mph}\qquad\textbf{(E)}\ 16\text{ mph} </math>
==Solution==
==Solution==
Unsolved
{{Solution}}
 
== See Also ==
== See Also ==
{{AHSME 50p box|year=1951|num-b=27|num-a=29}}  
{{AHSME 50p box|year=1951|num-b=27|num-a=29}}  

Revision as of 14:58, 19 April 2014

Problem

The pressure $(P)$ of wind on a sail varies jointly as the area $(A)$ of the sail and the square of the velocity $(V)$ of the wind. The pressure on a square foot is $1$ pound when the velocity is $16$ miles per hour. The velocity of the wind when the pressure on a square yard is $36$ pounds is:

$\textbf{(A)}\ 10\frac{2}{3}\text{ mph}\qquad\textbf{(B)}\ 96\text{ mph}\qquad\textbf{(C)}\ 32\text{ mph}\qquad\textbf{(D)}\ 1\frac{2}{3}\text{ mph}\qquad\textbf{(E)}\ 16\text{ mph}$

Solution

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See Also

1951 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 27
Followed by
Problem 29
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All AHSME Problems and Solutions

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