Art of Problem Solving

2011 AMC 10A Problems/Problem 2: Difference between revisions

Nathan wailes (talk | contribs)
No edit summary
Line 15: Line 15:
== See Also ==
== See Also ==
{{AMC10 box|year=2011|ab=A|num-b=1|num-a=3}}
{{AMC10 box|year=2011|ab=A|num-b=1|num-a=3}}
{{MAA Notice}}

Revision as of 11:00, 4 July 2013

Problem 2

A small bottle of shampoo can hold 35 milliliters of shampoo, whereas a large bottle can hold 500 milliliters of shampoo. Jasmine wants to buy the minimum number of small bottles necessary to completely fill a large bottle. How many bottles must she buy?

$\textbf{(A)}\ 11 \qquad\textbf{(B)}\ 12 \qquad\textbf{(C)}\ 13\qquad\textbf{(D)}\ 14\qquad\textbf{(E)}\ 15$

Solution

You want to find the minimum number of small bottles: so you do $\frac{500}{35} \approx 14.3$ which you round to $15$.


The answer is $\mathbf{\boxed{15\text{(E)}}}$.

See Also

2011 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

These problems are copyrighted © by the Mathematical Association of America.