Art of Problem Solving

2012 AMC 10A Problems/Problem 4: Difference between revisions

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== Problem 4 ==
== Problem 4 ==


Let <math>\angle ABC = 24</math>° and <math>\angle ABD = 20</math>°. What is the smallest possible degree measure for <math>\angle CBD?
Let <math>\angle ABC = 24</math>° and <math>\angle ABD = 20</math>°. What is the smallest possible degree measure for <math>\angle CBD ?


</math> \textbf{(A)}\ 0\qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 4\qquad\textbf{(D)}\ 6\qquad\textbf{(E)}\ 12 $
</math> \textbf{(A)}\ 0\qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 4\qquad\textbf{(D)}\ 6\qquad\textbf{(E)}\ 12 $

Revision as of 18:41, 8 February 2012

Problem 4

Let $\angle ABC = 24$° and $\angle ABD = 20$°. What is the smallest possible degree measure for $\angle CBD ?$ \textbf{(A)}\ 0\qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 4\qquad\textbf{(D)}\ 6\qquad\textbf{(E)}\ 12 $