Art of Problem Solving

AoPS Wiki talk:Problem of the Day/July 3, 2011: Difference between revisions

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{{:AoPSWiki:Problem of the Day/July 3, 2011}}
==Solution==
==Solution==
{{potd_solution}}
If <math>x</math> and <math>y</math> vary inversely, then <math>xy = k</math> where <math>k</math> is a constant.  We are given <math>x = 5</math> and <math>y = 8</math>, so <math>k = 40</math>.  Now, we want to find <math>x</math> when <math>y = 10</math>, so we divide <math>40</math> by <math>10</math> to get <math>\boxed{4}</math>.

Latest revision as of 09:18, 3 July 2011

Problem

AoPSWiki:Problem of the Day/July 3, 2011

Solution

If $x$ and $y$ vary inversely, then $xy = k$ where $k$ is a constant. We are given $x = 5$ and $y = 8$, so $k = 40$. Now, we want to find $x$ when $y = 10$, so we divide $40$ by $10$ to get $\boxed{4}$.