Art of Problem Solving

2005 AMC 10A Problems/Problem 3: Difference between revisions

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==Problem==
#REDIRECT [[2005 AMC 12A Problems/Problem 2]]
The equations <math> 2x + 7 = 3 </math> and <math> bx - 10 = -2 </math> have the same solution <math>x</math>. What is the value of <math>b</math>?
 
<math> \mathrm{(A) \ } -8\qquad \mathrm{(B) \ } -4\qquad \mathrm{(C) \ } -2\qquad \mathrm{(D) \ } 4\qquad \mathrm{(E) \ } 8 </math>
 
==Solution==
<math> 2x + 7 = 3 </math>
 
<math> x = -2 </math>
 
<math> bx - 10 = -2 </math>
 
<math> -2b - 10 = -2 </math>
 
<math> b = -4 \Rightarrow B </math>
 
==See Also==
*[[2005 AMC 10A Problems]]
 
*[[2005 AMC 10A Problems/Problem 2|Previous Problem]]
 
*[[2005 AMC 10A Problems/Problem 4|Next Problem]]
 
[[Category:Introductory Algebra Problems]]

Latest revision as of 21:02, 21 June 2009