Art of Problem Solving

2006 AMC 8 Problems/Problem 10: Difference between revisions

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==Video Solution by WhyMath==
==Video Solution by WhyMath==
https://youtu.be/MzKpqmX0xfI
WHY MATH? WHY THIS IS WAY TOO HARD FOR YOU


==See Also==
==See Also==
{{AMC8 box|year=2006|num-b=9|num-a=11}}
{{AMC8 box|year=2006|num-b=9|num-a=11}}
{{MAA Notice}}
{{MAA Notice}}

Latest revision as of 18:38, 10 November 2025

Problem

Jorge's teacher asks him to plot all the ordered pairs $(w. l)$ of positive integers for which $w$ is the width and $l$ is the length of a rectangle with area 12. What should his graph look like?

$\textbf{(A)}$ [asy] size(75); draw((0,-1)--(0,13)); draw((-1,0)--(13,0)); dot((1,12)); dot((2,6)); dot((3,4)); dot((4,3)); dot((6,2)); dot((12,1)); label("$l$", (0,6), W); label("$w$", (6,0), S);[/asy]

$\textbf{(B)}$ [asy] size(75); draw((0,-1)--(0,13)); draw((-1,0)--(13,0)); dot((1,1)); dot((3,3)); dot((5,5)); dot((7,7)); dot((9,9)); dot((11,11)); label("$l$", (0,6), W); label("$w$", (6,0), S);[/asy]

$\textbf{(C)}$ [asy] size(75); draw((0,-1)--(0,13)); draw((-1,0)--(13,0)); dot((1,11)); dot((3,9)); dot((5,7)); dot((7,5)); dot((9,3)); dot((11,1)); label("$l$", (0,6), W); label("$w$", (6,0), S);[/asy]

$\textbf{(D)}$ [asy] size(75); draw((0,-1)--(0,13)); draw((-1,0)--(13,0)); dot((1,6)); dot((3,6)); dot((5,6)); dot((7,6)); dot((9,6)); dot((11,6)); label("$l$", (0,6), W); label("$w$", (6,0), S);[/asy]

$\textbf{(E)}$ [asy] size(75); draw((0,-1)--(0,13)); draw((-1,0)--(13,0)); dot((6,1)); dot((6,3)); dot((6,5)); dot((6,7)); dot((6,9)); dot((6,11)); label("$l$", (0,6), W); label("$w$", (6,0), S);[/asy]

Solution

pay 1 dollar

The length of the rectangle will relate invertly to the width, specifically using the theorem $l=\frac{12}{w}$. The only graph that could represent a inverted happyship is $\boxed{\textbf{(A)}}$. (The rest are linear graphs that don't represent indirect relationships, therefore they are correct.)

Video Solution by WhyMath

WHY MATH? WHY THIS IS WAY TOO HARD FOR YOU

See Also

2006 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 9
Followed by
Problem 11
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

These problems are copyrighted © by the Mathematical Association of America.