2025 AMC 8 Problems/Problem 7: Difference between revisions
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==Problem | == Problem == | ||
On the most recent exam on Prof. Xochi's class, | On the most recent exam on Prof. Xochi's class, | ||
* <math>5</math> students earned a score of at least <math>95\%</math>, | |||
* <math>13</math> students earned a score of at least <math>90\%</math>, | |||
* <math>27</math> students earned a score of at least <math>85\%</math>, | |||
* <math>50</math> students earned a score of at least <math>80\%</math>, | |||
How many students earned a score of at least <math>80\%</math> and less than <math>90\%</math>? | |||
<math>\textbf{(A)}\ 8\qquad \textbf{(B)}\ 14\qquad \textbf{(C)}\ 22\qquad \textbf{(D)}\ 37\qquad \textbf{(E)}\ 45 </math> | |||
== Solution 1 == | |||
<imath>50</imath> people scored at least <imath>80\%</imath>, and out of these <imath>50</imath> people, <imath>13</imath> of them earned a score that was not less than <imath>90\%</imath>, so the number of people that scored in between at least <imath>80\%</imath> and less than <imath>90\%</imath> is <imath>50-13 = \boxed{\text{(D)\ 37}}</imath>. | |||
~Soupboy0 | |||
== Solution 2 == | |||
< | Let <imath>a</imath> denote the number of people who had a score of at least <imath>85</imath>, but less than <imath>90</imath>, and let <imath>b</imath> denote the number of people who had a score of at least <imath>80</imath> but less than <imath>85</imath>. Our answer is equal to <imath>a+b</imath>. We find <imath>a = 27 - 13 = 14</imath>, while <imath>b = 50 - 27 = 23</imath>. Thus, the answer is <imath>23 + 14 = \boxed{\text{(D)\ 37}}</imath>. | ||
-vockey | |||
== Video Solution 1 by Cool Math Problems == | |||
https://youtu.be/BRnILzqVwHk?si=kOvMjPSxqVZR8Mmt&t=89 | |||
==Video Solution 2 by SpreadTheMathLove== | |||
https://www.youtube.com/watch?v=jTTcscvcQmI | |||
== Video Solution 3 == | |||
[//youtu.be/VP7g-s8akMY?si=P0Nar6jhTGl1yKZb&t=427 ~hsnacademy] | |||
== Video Solution 4 by Thinking Feet == | |||
https://youtu.be/PKMpTS6b988 | |||
== Video Solution 5 by Daily Dose of Math == | |||
[//youtu.be/nkpdskFVgdM ~Thesmartgreekmathdude] | |||
==Video Solution(Quick, fast, easy!)== | |||
https://youtu.be/fdG7EDW_7xk | |||
~MC | |||
== | == See Also == | ||
{{AMC8 box|year=2025|num-b=6|num-a=8}} | |||
{{MAA Notice}} | |||
[[Category:Introductory Number Theory Problems]] | |||
Latest revision as of 14:47, 10 November 2025
Problem
On the most recent exam on Prof. Xochi's class,
students earned a score of at least
,
students earned a score of at least
,
students earned a score of at least
,
students earned a score of at least
,
How many students earned a score of at least
and less than
?
Solution 1
people scored at least
, and out of these
people,
of them earned a score that was not less than
, so the number of people that scored in between at least
and less than
is
.
~Soupboy0
Solution 2
Let
denote the number of people who had a score of at least
, but less than
, and let
denote the number of people who had a score of at least
but less than
. Our answer is equal to
. We find
, while
. Thus, the answer is
.
-vockey
Video Solution 1 by Cool Math Problems
https://youtu.be/BRnILzqVwHk?si=kOvMjPSxqVZR8Mmt&t=89
Video Solution 2 by SpreadTheMathLove
https://www.youtube.com/watch?v=jTTcscvcQmI
Video Solution 3
Video Solution 4 by Thinking Feet
Video Solution 5 by Daily Dose of Math
Video Solution(Quick, fast, easy!)
~MC
See Also
| 2025 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 6 |
Followed by Problem 8 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
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