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| (Problem goes here)
| | #redirect [[2025 AMC 12A Problems/Problem 15]] |
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| ==Solution 1==
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| Let our subset be <imath>\{11,12,13,...,20\}.</imath> If we add any one element from the set <imath>\{1,2,3,...,10\},</imath> we will have to remove at least one element from our current subset. Hence, the size of our set cannot exceed <imath>\boxed{\text{(C) }10}.</imath>
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| ~Tacos_are_yummy_1
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| ==Solution 2==
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| Let our subset be <imath>\{1,3,5,...,19\}.</imath> Since odd numbers + odd numbers will always sum to an even number, this subset holds true. Leo, the addition of any even number will result in a violation of the rule, so the maximum number of elements is <imath>\boxed{\text{(C) }10}.</imath>
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| ~KMS888
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| ==See also==
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| {{AMC10 box|year=2025|ab=A|num-b=20|num-a=22}}
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| {{AMC12 box|year=2025|ab=A|num-b=17|num-a=19}}
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| {{MAA Notice}}
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