2010 AMC 12A Problems/Problem 1: Difference between revisions
Created page with '== Problem 1 == What is <math>\left(20-\left(2010-201\right)\right)+\left(2010-\left(201-20\right)\right)</math>? <math>\textbf{(A)}\ -4020 \qquad \textbf{(B)}\ 0 \qquad \textbf…' |
|||
| (11 intermediate revisions by 8 users not shown) | |||
| Line 1: | Line 1: | ||
== Problem | == Problem == | ||
What is <math>\left(20-\left(2010-201\right)\right)+\left(2010-\left(201-20\right)\right)</math>? | What is <math>\left(20-\left(2010-201\right)\right)+\left(2010-\left(201-20\right)\right)</math>? | ||
<math>\textbf{(A)}\ -4020 \qquad \textbf{(B)}\ 0 \qquad \textbf{(C)}\ 40 \qquad \textbf{(D)}\ 401 \qquad \textbf{(E)}\ 4020</math> | <math>\textbf{(A)}\ -4020 \qquad \textbf{(B)}\ 0 \qquad \textbf{(C)}\ 40 \qquad \textbf{(D)}\ 401 \qquad \textbf{(E)}\ 4020</math> | ||
== Solution == | |||
<math>20-2010+201+2010-201+20=20+20=\boxed{\textbf{(C)}\,40}</math>. | |||
==Video Solution== | |||
https://youtu.be/KBlf0TKdI4I?si=XFer3NW2lpMxgjW_ | |||
== See Also == | |||
{{AMC12 box|year=2010|before=First Problem|num-a=2|ab=A}} | |||
[[Category:Introductory Algebra Problems]] | |||
{{MAA Notice}} | |||
Latest revision as of 00:16, 11 October 2025
Problem
What is
?
Solution
.
Video Solution
https://youtu.be/KBlf0TKdI4I?si=XFer3NW2lpMxgjW_
See Also
| 2010 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by First Problem |
Followed by Problem 2 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
These problems are copyrighted © by the Mathematical Association of America.