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2011 AMC 8 Problems/Problem 1: Difference between revisions

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==Problem==
==Problem==
Margie bought <math> 3 </math> apples at a cost of <math> 50 </math> cents per apple. She paid with a 5-dollar bill. How much change did Margie recieve?
Margie bought <math> 3 </math> apples at a cost of <math> 50 </math> cents per apple. She paid with a 5-dollar bill. How much change did Margie receive?


<math>\text{(A)}\ \textdollar 1.50 \qquad \text{(B)}\ \textdollar 2.00 \qquad \text{(C)}\ \textdollar 2.50 \qquad \text{(D)}\ \textdollar 3.00 \qquad \text{(E)}\ \textdollar 3.50</math>
<math>\textbf{(A)}\ \textdollar 1.50 \qquad \textbf{(B)}\ \textdollar 2.00 \qquad \textbf{(C)}\ \textdollar 2.50 \qquad \textbf{(D)}\ \textdollar 3.00 \qquad \textbf{(E)}\ \textdollar 3.50</math>


==Solution==
==Solution==
<math>50</math> cents is equivalent to <math>\textdollar 0.50.</math> Then the three apples cost <math>3 \times \textdollar 0.50 = \textdollar 1.50.</math> The change Margie receives is <math>\textdollar 5.00 - \textdollar 1.50 = \boxed{\textbf{(E)}\ \textdollar 3.50}</math>
-Mathloveraldoxxx5223
==Video Solution by WhyMath==
https://youtu.be/fOjqS0hU5Rc


==See Also==
==See Also==
{{AMC8 box|year=2011|num-b=|num-a=2}}
{{AMC8 box|year=2011|before=First Problem|num-a=2}}
{{MAA Notice}}

Latest revision as of 10:01, 18 November 2024

Problem

Margie bought $3$ apples at a cost of $50$ cents per apple. She paid with a 5-dollar bill. How much change did Margie receive?

$\textbf{(A)}\ \textdollar 1.50 \qquad \textbf{(B)}\ \textdollar 2.00 \qquad \textbf{(C)}\ \textdollar 2.50 \qquad \textbf{(D)}\ \textdollar 3.00 \qquad \textbf{(E)}\ \textdollar 3.50$

Solution

$50$ cents is equivalent to $\textdollar 0.50.$ Then the three apples cost $3 \times \textdollar 0.50 = \textdollar 1.50.$ The change Margie receives is $\textdollar 5.00 - \textdollar 1.50 = \boxed{\textbf{(E)}\ \textdollar 3.50}$

-Mathloveraldoxxx5223

Video Solution by WhyMath

https://youtu.be/fOjqS0hU5Rc

See Also

2011 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

These problems are copyrighted © by the Mathematical Association of America.